Sec 1 Maths Coordinates and linear graphs worksheet with answers
A free Sec 1 Maths worksheet on coordinates and linear graphs: 8 questions, 30 marks, short questions first and then structured ones, in the school exam style. The answers and full worked solutions are on the last page.
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Answer all questions. Show all your working. Give non-exact answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless the question says otherwise.
Section A
1
The graph shows the taxi fare, $y, for a trip of x km. Use the graph to find the fare for a trip of 10 km.
Answer[1]
2
State whether the gradient of the line shown is positive, negative, zero or not defined.
Answer[1]
3
ABCD is a rectangle. The points A, B and C are shown. Find the coordinates of D.
Answer[2]
4
Write down the coordinates of the point E.
Answer[2]
5
(a)Complete the table of values for y=−4x−5.
Answer (a)[3]
(b)Complete the table of values for 4x−y=−7.
Answer (b)[3]
Section B
6
(a)The graph shows the height, y cm, of a candle x hours after it is lit. The candle burns at a steady rate. Find this rate, in cm per hour.
Answer (a)[2]
(b)Complete the table of values for 4x−y=−5.
Answer (b)[3]
7
(a)The line passes through the points A and B shown. Find its gradient.
Answer (a)[2]
(b)The graph shows the taxi fare, $y, for a trip of x km. Assuming that the line continues in the same way, find the fare for a trip of 15 km.
Answer (b)[3]
8
(a)P is the point (−1,−4) and Q is the point (2,−4). Find the length of PQ.
Answer (a)units[1]
(b)The graph shows the length, y cm, of a spring when a mass of x kg hangs from it. Use the graph to find the length of the spring when a mass of 6 kg hangs from it.
Answer (b)[1]
(c)(i)Complete the table of values for y=2x−4.
Answer (c)(i)[3]
(c)(ii)Complete the table of values for 4x+y=2.
Answer (c)(ii)[3]
END OF PAPER
Answers and worked solutions
Question 1
Answer: Fare: $23[1]
Fare: $23
Question 2
Answer: POSITIVE[1]
The line goes up from left to right.So the gradient is positive.
Question 3
Answer: So D(−2,1).[2]
Across: 2−2=0Up: 1−(−5)=6x=−2y=1So D(−2,1).
Question 4
Answer: So E(−3,4).[2]
x=−3y=4So E(−3,4).
Question 5
(a)Answer: y=−17[3]
When x=−2: y=−4(−2)−5y=3When x=−1: y=−4(−1)−5y=−1When x=3: y=−4(3)−5y=−17