Sec 1 Maths · Coordinates and linear graphs

Table of values questions with answers

Practice questions on table of values, from the basics up to exam level, each with a full worked solution. Try them on paper first, then open the solution to check your working.

Worked example

Complete the table of values for $y = 4x - 2$ .

Step 1 of 1

Put each missing x into y = mx + c (negatives in brackets)

When

x = -2

y = 4(-2) - 2

y = -10

When

x = -1

y = 4(-1) - 2

y = -6

When

x = 1

y = 4(1) - 2

y = 2

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Questions

Question 1y = mx + c, positive gradient
Complete the table of values for $y = 4x - 1$ .
Show the worked solution
1. Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -2$ : $y = 4(-2) - 1$ $y = -9$ When $x = -1$ : $y = 4(-1) - 1$ $y = -5$ When $x = 1$ : $y = 4(1) - 1$ $y = 3$
Question 2y = mx + c, positive gradient
Complete the table of values for $y = x + 1$ .
Show the worked solution
1. Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -2$ : $y = (-2) + 1$ $y = -1$ When $x = -1$ : $y = (-1) + 1$ $y = 0$ When $x = 3$ : $y = (3) + 1$ $y = 4$
Question 3Negative gradient
Complete the table of values for $y = -3x + 5$ .
Show the worked solution
1. Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -1$ : $y = -3(-1) + 5$ $y = 8$ When $x = 3$ : $y = -3(3) + 5$ $y = -4$ When $x = 4$ : $y = -3(4) + 5$ $y = -7$
Question 4Negative gradient
Complete the table of values for $y = -x + 3$ .
Show the worked solution
1. Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -2$ : $y = -(-2) + 3$ $y = 5$ When $x = -1$ : $y = -(-1) + 3$ $y = 4$ When $x = 1$ : $y = -(1) + 3$ $y = 2$
Question 5Rearrange ax + by = c first
Complete the table of values for $x - y = 1$ .
Show the worked solution
1. Step 1: Make y the subject: move the x term across, then divide every term by the number in front of y $-y = -x + 1$ $y = x - 1$
2. Step 2: Put each missing x into y = mx + c (negatives in brackets)When $x = -3$ : $y = (-3) - 1$ $y = -4$ When $x = -1$ : $y = (-1) - 1$ $y = -2$ When $x = 1$ : $y = (1) - 1$ $y = 0$
Question 6Rearrange ax + by = c first
Complete the table of values for $4x + 2y = -6$ .
Show the worked solution
1. Step 1: Make y the subject: move the x term across, then divide every term by the number in front of y $2y = -4x - 6$ $y = -2x - 3$
2. Step 2: Put each missing x into y = mx + c (negatives in brackets)When $x = -3$ : $y = -2(-3) - 3$ $y = 3$ When $x = -2$ : $y = -2(-2) - 3$ $y = 1$ When $x = 2$ : $y = -2(2) - 3$ $y = -7$

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Worked example

Complete the table of values for

y = 4x - 2

Step 1 of 1

Put each missing x into y = mx + c (negatives in brackets)

When

x = -2

y = 4(-2) - 2

y = -10

When

x = -1

y = 4(-1) - 2

y = -6

When

x = 1

y = 4(1) - 2

y = 2

Questions

Question 1y = mx + c, positive gradient

Complete the table of values for $y = 4x - 1$ .

Show the worked solution

Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -2$ : $y = 4(-2) - 1$ $y = -9$ When $x = -1$ : $y = 4(-1) - 1$ $y = -5$ When $x = 1$ : $y = 4(1) - 1$ $y = 3$

Question 2y = mx + c, positive gradient

Complete the table of values for $y = x + 1$ .

Show the worked solution

Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -2$ : $y = (-2) + 1$ $y = -1$ When $x = -1$ : $y = (-1) + 1$ $y = 0$ When $x = 3$ : $y = (3) + 1$ $y = 4$

Question 3Negative gradient

Complete the table of values for $y = -3x + 5$ .

Show the worked solution

Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -1$ : $y = -3(-1) + 5$ $y = 8$ When $x = 3$ : $y = -3(3) + 5$ $y = -4$ When $x = 4$ : $y = -3(4) + 5$ $y = -7$

Question 4Negative gradient

Complete the table of values for $y = -x + 3$ .

Show the worked solution

Step 1: Put each missing x into y = mx + c (negatives in brackets)When $x = -2$ : $y = -(-2) + 3$ $y = 5$ When $x = -1$ : $y = -(-1) + 3$ $y = 4$ When $x = 1$ : $y = -(1) + 3$ $y = 2$

Question 5Rearrange ax + by = c first

Complete the table of values for $x - y = 1$ .

Show the worked solution

Step 1: Make y the subject: move the x term across, then divide every term by the number in front of y $-y = -x + 1$ $y = x - 1$
Step 2: Put each missing x into y = mx + c (negatives in brackets)When $x = -3$ : $y = (-3) - 1$ $y = -4$ When $x = -1$ : $y = (-1) - 1$ $y = -2$ When $x = 1$ : $y = (1) - 1$ $y = 0$

Question 6Rearrange ax + by = c first

Complete the table of values for $4x + 2y = -6$ .

Show the worked solution

Step 1: Make y the subject: move the x term across, then divide every term by the number in front of y $2y = -4x - 6$ $y = -2x - 3$
Step 2: Put each missing x into y = mx + c (negatives in brackets)When $x = -3$ : $y = -2(-3) - 3$ $y = 3$ When $x = -2$ : $y = -2(-2) - 3$ $y = 1$ When $x = 2$ : $y = -2(2) - 3$ $y = -7$