Sec 1 G1 Maths Ratio worksheet with answers

A free Sec 1 G1 Maths worksheet on ratio: 6 questions, 30 marks, short questions first and then structured ones, in the school exam style. The answers and full worked solutions are on the last page.

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Sec 1 G1 Maths worksheet: Ratio

Total: 30 marksSuggested time: 50 minutes

Name: ______________________________Class: ____________ Date: ____________

Answer all questions. Show all your working. Give non-exact answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless the question says otherwise.

Section A

Express the ratio

250

:

2.5

km in its simplest form.

Answer[2]

The ratio of Siti's stickers to Devi's stickers is

3 : 5

. Devi has 20 stickers. Find the total number of stickers they have.

Answer[2]

(a)Devi and Kumar share 75 stamps in the ratio

2 : 3

. Find the number of stamps Kumar gets.

Answer (a)[3]

(b)The ratio of Ravi's savings to Chen Wei's savings is

7 : 4

. Ravi has $24 more than Chen Wei. Find the amount of money Ravi has.

Answer (b)$[2]

(a)Hui Min and Nur share 125 stickers in the ratio

2 : 3

. Find the number of stickers Nur gets.

Answer (a)[3]

(b)Kumar and Siti share 48 stamps in the ratio

3 : 5

. Find the number of stamps Siti gets.

Answer (b)[3]

Section B

(a)Express

18 : 42 : 12

in its simplest form.

Answer (a)[2]

(b)(i)The ratio of Mei Ling's stickers to Ali's stickers is

2 : 7

. Ali has 84 stickers. Find the number of stickers Mei Ling has.

Answer (b)(i)[2]

(b)(ii)Siti, Devi and Kumar share $180 in the ratio

6 : 1 : 2

. Find the amount Kumar receives.

Answer (b)(ii)$[3]

(a)(i)Express the ratio

750

:

2.5

km in its simplest form.

Answer (a)(i)[2]

(a)(ii)Express the ratio

20

:

3

m in its simplest form.

Answer (a)(ii)[2]

(b)(i)The ratio of Devi's savings to Kumar's savings is

9 : 4

. Devi has $108. Find the total amount of money they have.

Answer (b)(i)$[2]

(b)(ii)The ratio of Ravi's stamps to Chen Wei's stamps is

1 : 3

. Chen Wei has 12 more stamps than Ravi. Find the number of stamps Chen Wei has.

Answer (b)(ii)[2]

END OF PAPER

Answers and worked solutions

Question 1

Answer:

\phantom{250 : 2500} = 1 : 10

[2]

2.5 \text{ km} = 2.5 \times 1000 \text{ m}

\phantom{2.5 \text{ km}} = 2500 \text{ m}

\text{HCF of } 250 \text{ and } 2500 = 250

250 : 2500 = \dfrac{250}{250} : \dfrac{2500}{250}

\phantom{250 : 2500} = 1 : 10

Question 2

Answer: Altogether they have

32

stickers.[2]

5 \text{ units} \rightarrow 20

1 \text{ unit} \rightarrow \dfrac{20}{5} = 4

8 \text{ units} \rightarrow 8 \times 4 = 32

Altogether they have

32

stickers.

Question 3

(a)Answer: Kumar gets

45

stamps.[3]

\text{Total} = 2 + 3

\phantom{\text{Total}} = 5 \text{ units}

5 \text{ units} \rightarrow 75

1 \text{ unit} \rightarrow \dfrac{75}{5} = 15

3 \text{ units} \rightarrow 3 \times 15 = 45

Kumar gets

45

stamps.

(b)Answer: Ravi has $56.[2]

7 - 4 = 3 \text{ units}

3 \text{ units} \rightarrow 24

1 \text{ unit} \rightarrow \dfrac{24}{3} = 8

7 \text{ units} \rightarrow 7 \times 8 = 56

Ravi has $56.

Question 4

(a)Answer: Nur gets

75

stickers.[3]

\text{Total} = 2 + 3

\phantom{\text{Total}} = 5 \text{ units}

5 \text{ units} \rightarrow 125

1 \text{ unit} \rightarrow \dfrac{125}{5} = 25

3 \text{ units} \rightarrow 3 \times 25 = 75

Nur gets

75

stickers.

(b)Answer: Siti gets

30

stamps.[3]

\text{Total} = 3 + 5

\phantom{\text{Total}} = 8 \text{ units}

8 \text{ units} \rightarrow 48

1 \text{ unit} \rightarrow \dfrac{48}{8} = 6

5 \text{ units} \rightarrow 5 \times 6 = 30

Siti gets

30

stamps.

Question 5

(a)Answer:

\phantom{18 : 42 : 12} = 3 : 7 : 2

[2]

\text{HCF of } 18, 42 \text{ and } 12 = 6

18 : 42 : 12 = \dfrac{18}{6} : \dfrac{42}{6} : \dfrac{12}{6}

\phantom{18 : 42 : 12} = 3 : 7 : 2

(b)(i)Answer: Mei Ling has

24

stickers.[2]

7 \text{ units} \rightarrow 84

1 \text{ unit} \rightarrow \dfrac{84}{7} = 12

2 \text{ units} \rightarrow 2 \times 12 = 24

Mei Ling has

24

stickers.

(b)(ii)Answer: Kumar receives $40.[3]

\text{Total} = 6 + 1 + 2

\phantom{\text{Total}} = 9 \text{ units}

9 \text{ units} \rightarrow 180

1 \text{ unit} \rightarrow \dfrac{180}{9} = 20

2 \text{ units} \rightarrow 2 \times 20 = 40

Kumar receives $40.

Question 6

(a)(i)Answer:

\phantom{750 : 2500} = 3 : 10

[2]

2.5 \text{ km} = 2.5 \times 1000 \text{ m}

\phantom{2.5 \text{ km}} = 2500 \text{ m}

\text{HCF of } 750 \text{ and } 2500 = 250

750 : 2500 = \dfrac{750}{250} : \dfrac{2500}{250}

\phantom{750 : 2500} = 3 : 10

(a)(ii)Answer:

\phantom{20 : 300} = 1 : 15

[2]

3 \text{ m} = 3 \times 100 \text{ cm}

\phantom{3 \text{ m}} = 300 \text{ cm}

\text{HCF of } 20 \text{ and } 300 = 20

20 : 300 = \dfrac{20}{20} : \dfrac{300}{20}

\phantom{20 : 300} = 1 : 15

(b)(i)Answer: Altogether they have $156.[2]

9 \text{ units} \rightarrow 108

1 \text{ unit} \rightarrow \dfrac{108}{9} = 12

13 \text{ units} \rightarrow 13 \times 12 = 156

Altogether they have $156.

(b)(ii)Answer: Chen Wei has

18

stamps.[2]

3 - 1 = 2 \text{ units}

2 \text{ units} \rightarrow 12

1 \text{ unit} \rightarrow \dfrac{12}{2} = 6

3 \text{ units} \rightarrow 3 \times 6 = 18

Chen Wei has

18

stamps.

Sec 1 G1 Maths Ratio worksheet with answers

A free Sec 1 G1 Maths worksheet on ratio: 6 questions, 30 marks, short questions first and then structured ones, in the school exam style. The answers and full worked solutions are on the last page.

In the print window, choose Save as PDF to download it.

Or practise it online with step-by-step help when you get one wrong.

Section B

(a)Express

18 : 42 : 12

in its simplest form.

Answer (a)[2]

(b)(i)The ratio of Mei Ling's stickers to Ali's stickers is

2 : 7

. Ali has 84 stickers. Find the number of stickers Mei Ling has.

Answer (b)(i)[2]

(b)(ii)Siti, Devi and Kumar share $180 in the ratio

6 : 1 : 2

. Find the amount Kumar receives.

Answer (b)(ii)$[3]

Answers and worked solutions

Question 1

Answer:

\phantom{250 : 2500} = 1 : 10

[2]

2.5 \text{ km} = 2.5 \times 1000 \text{ m}

\phantom{2.5 \text{ km}} = 2500 \text{ m}

\text{HCF of } 250 \text{ and } 2500 = 250

250 : 2500 = \dfrac{250}{250} : \dfrac{2500}{250}

\phantom{250 : 2500} = 1 : 10

Question 2

Answer: Altogether they have

32

stickers.[2]

5 \text{ units} \rightarrow 20

1 \text{ unit} \rightarrow \dfrac{20}{5} = 4

8 \text{ units} \rightarrow 8 \times 4 = 32

Altogether they have

32

stickers.

Question 3

(a)Answer: Kumar gets

45

stamps.[3]

\text{Total} = 2 + 3

\phantom{\text{Total}} = 5 \text{ units}

5 \text{ units} \rightarrow 75

1 \text{ unit} \rightarrow \dfrac{75}{5} = 15

3 \text{ units} \rightarrow 3 \times 15 = 45

Kumar gets

45

stamps.

(b)Answer: Ravi has $56.[2]

7 - 4 = 3 \text{ units}

3 \text{ units} \rightarrow 24

1 \text{ unit} \rightarrow \dfrac{24}{3} = 8

7 \text{ units} \rightarrow 7 \times 8 = 56

Ravi has $56.

Question 4

(a)Answer: Nur gets

75

stickers.[3]

\text{Total} = 2 + 3

\phantom{\text{Total}} = 5 \text{ units}

5 \text{ units} \rightarrow 125

1 \text{ unit} \rightarrow \dfrac{125}{5} = 25

3 \text{ units} \rightarrow 3 \times 25 = 75

Nur gets

75

stickers.

(b)Answer: Siti gets

30

stamps.[3]

\text{Total} = 3 + 5

\phantom{\text{Total}} = 8 \text{ units}

8 \text{ units} \rightarrow 48

1 \text{ unit} \rightarrow \dfrac{48}{8} = 6

5 \text{ units} \rightarrow 5 \times 6 = 30

Siti gets

30

stamps.

Question 5

(a)Answer:

\phantom{18 : 42 : 12} = 3 : 7 : 2

[2]

\text{HCF of } 18, 42 \text{ and } 12 = 6

18 : 42 : 12 = \dfrac{18}{6} : \dfrac{42}{6} : \dfrac{12}{6}

\phantom{18 : 42 : 12} = 3 : 7 : 2

(b)(i)Answer: Mei Ling has

24

stickers.[2]

7 \text{ units} \rightarrow 84

1 \text{ unit} \rightarrow \dfrac{84}{7} = 12

2 \text{ units} \rightarrow 2 \times 12 = 24

Mei Ling has

24

stickers.

(b)(ii)Answer: Kumar receives $40.[3]

\text{Total} = 6 + 1 + 2

\phantom{\text{Total}} = 9 \text{ units}

9 \text{ units} \rightarrow 180

1 \text{ unit} \rightarrow \dfrac{180}{9} = 20

2 \text{ units} \rightarrow 2 \times 20 = 40

Kumar receives $40.

Question 6

(a)(i)Answer:

\phantom{750 : 2500} = 3 : 10

[2]

2.5 \text{ km} = 2.5 \times 1000 \text{ m}

\phantom{2.5 \text{ km}} = 2500 \text{ m}

\text{HCF of } 750 \text{ and } 2500 = 250

750 : 2500 = \dfrac{750}{250} : \dfrac{2500}{250}

\phantom{750 : 2500} = 3 : 10

(a)(ii)Answer:

\phantom{20 : 300} = 1 : 15

[2]

3 \text{ m} = 3 \times 100 \text{ cm}

\phantom{3 \text{ m}} = 300 \text{ cm}

\text{HCF of } 20 \text{ and } 300 = 20

20 : 300 = \dfrac{20}{20} : \dfrac{300}{20}

\phantom{20 : 300} = 1 : 15

(b)(i)Answer: Altogether they have $156.[2]

9 \text{ units} \rightarrow 108

1 \text{ unit} \rightarrow \dfrac{108}{9} = 12

13 \text{ units} \rightarrow 13 \times 12 = 156

Altogether they have $156.

(b)(ii)Answer: Chen Wei has

18

stamps.[2]

3 - 1 = 2 \text{ units}

2 \text{ units} \rightarrow 12

1 \text{ unit} \rightarrow \dfrac{12}{2} = 6

3 \text{ units} \rightarrow 3 \times 6 = 18

Chen Wei has

18

stamps.