Question 1nth term, going up
Find an expression, in terms of n, for the nth term of the sequence 1, 4, 7, 10, ….
Show the worked solution
- Step 1: Find the common difference: it is the number in front of n(4−1= 3
- Step 2: Compare with (difference)n, which starts at the difference: first term − difference = the number to add(1−3= −2
- Step 3: So the nth term is (difference)n + (the number to add)Tn=3n−2
Question 2nth term, going down
Find an expression, in terms of n, for the nth term of the sequence 40, 35, 30, 25, ….
Show the worked solution
- Step 1: Find the common difference: it is the number in front of n(35−40= −5
- Step 2: Compare with (difference)n, which starts at the difference: first term − difference = the number to add(40−(−5)= 45
- Step 3: So the nth term is (the number to add) + (difference)nTn=45−5n
Question 3Find a given term
Find the 20th term of the sequence −3, 0, 3, 6, ….
Show the worked solution
- Step 1: Find the common difference: it is the number in front of n(0−(−3)= 3
- Step 2: Compare with (difference)n, which starts at the difference: first term − difference = the number to add((−3)−3= −6
- Step 3: Write the nth termTn=3n−6
- Step 4: Put n = 20 into the nth term3×20−6=54
Question 4Is it a term?
Determine whether 107 is a term of the sequence 5, 8, 11, 14, ….
Show the worked solution
- Step 1: Find the common difference: it is the number in front of n(8−5= 3
- Step 2: Compare with (difference)n, which starts at the difference: first term − difference = the number to add(5−3= 2
- Step 3: Set the nth term equal to 107 and solve for n3n+2=107n=35
- Step 4: It is a term only if n is a whole numbern is a whole number, so 107 is the 35th term: Yes.
Question 5Square numbers in the nth term
Find an expression, in terms of n, for the nth term of the sequence 1, 7, 15, 25, ….
Show the worked solution
- Step 1: The differences go up by 2 each time: compare with the square numbers 1, 4, 9, 16Term minus n2: 0,3,6,9
- Step 2: What is left goes up by the same amount: find its nth term3n−3
- Step 3: So the nth term is n² plus thatTn=n2+3n−3
Question 6Sequences of fractions
Find an expression, in terms of n, for the nth term of the sequence 74, 116, 158, 1910, ….
Show the worked solution
- Step 1: The numerators go up by the same amount each time: find their nth term2n+2
- Step 2: Do the same for the denominators4n+3
- Step 3: So the nth term isTn=4n+32n+2