Sec 1 Maths Percentage worksheet with answers

A free Sec 1 Maths worksheet on percentage: 6 questions, 30 marks, short questions first and then structured ones, in the school exam style. The answers and full worked solutions are on the last page.

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Sec 1 Maths worksheet: Percentage

Total: 30 marksSuggested time: 45 minutes

Name: ______________________________Class: ____________ Date: ____________

Answer all questions. Show all your working. Give non-exact answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless the question says otherwise.

Section A

Ben borrows $4,000 from a bank at 5% per annum simple interest. Find the interest Ben has to pay after 2 years.

Answer$[2]

Item	Price
Tom yum soup	$11.80
Teh tarik	$2.80
Lime juice	$3.40
Chendol	$4.40

The table shows the food a family ordered at a restaurant. Members get a 20% discount on the food, then a 10% service charge is added, and then 9% GST is charged on the total. The family are members. Find the amount they pay, correct to the nearest cent.

Answer$[3]

(a)A family used 18 m³ of water in March. In April they used 20% less. Find the volume of water, in m³, they used in April.

Answer (a)[2]

(b)A bicycle cost $240 last year. Its price has fallen by 10%. Find its price now.

Answer (b)$[2]

Section B

(a)The marked price of a rice cooker is $30. During a sale it is sold for $26.25. Find the percentage discount.

Answer (a)%[2]

(b)(i)A family used 20 m³ of water in March. In April they used 25% less. Find the volume of water, in m³, they used in April.

Answer (b)(i)[2]

(b)(ii)A family's monthly electricity bill fell from $400 to $380. Find the percentage decrease.

Answer (b)(ii)%[2]

(a)(i)Express

60

as a percentage of

64

Answer (a)(i)%[1]

(a)(ii)Express

100

g as a percentage of

2.5

kg.

Answer (a)(ii)%[2]

(b)(i)A trader bought a pair of earphones for $60 and sold it for $54. Find the percentage loss.

Answer (b)(i)%[2]

(b)(ii)The marked price of a school bag is $400. During a sale it is sold for $360. Find the percentage discount.

Answer (b)(ii)%[2]

(a)The monthly rent of a shop went up by 10% to $2,200. Find the rent before the increase.

Answer (a)$[2]

(b)The number of cups of coffee a café sold in 2024 was 4,320. This was 20% more than in 2023. In 2025, the number was 3,456. Find the percentage decrease in the number of cups of coffee a café sold from 2023 to 2025.

Answer (b)%[3]

Hire purchase	Piano
Cash price	$6,000
Deposit	25% of the cash price
Monthly instalments	18 instalments of $272.50

(c)The table shows the terms for buying a piano on hire purchase. Find how much more the piano costs on hire purchase than for cash.

Answer (c)$[3]

END OF PAPER

Answers and worked solutions

Question 1

Answer: The interest is $400.[2]

I = \dfrac{PRT}{100}

I = \dfrac{4000 \times 5 \times 2}{100}

= 400

The interest is $400.

Question 2

Answer: The family pays $21.49.[3]

11.80 + 2.80 + 3.40 + 4.40 = 22.40

22.40 \times \dfrac{80}{100} = 17.92

17.92 \times \dfrac{110}{100} = 19.712

19.712 \times \dfrac{109}{100} = 21.48608

\approx 21.49

(to the nearest cent)The family pays $21.49.

Question 3

(a)Answer: They used

14.4

m³ of water in April.[2]

100\% - 20\% = 80\%

\text{New value} = \dfrac{80}{100} \times 18

= 14.4

They used

14.4

m³ of water in April.

(b)Answer: Its price now is $216.[2]

100\% - 10\% = 90\%

\text{New value} = \dfrac{90}{100} \times 240

= 216

Its price now is $216.

Question 4

(a)Answer:

= 12.5\%

[2]

\text{Discount} = 30 - 26.25

\phantom{\text{Discount}} = 3.75

\text{Percentage discount} = \dfrac{3.75}{30} \times 100\%

= 12.5\%

(b)(i)Answer: They used

15

m³ of water in April.[2]

100\% - 25\% = 75\%

\text{New value} = \dfrac{75}{100} \times 20

= 15

They used

15

m³ of water in April.

(b)(ii)Answer:

= 5\%

[2]

\text{Decrease} = 400 - 380

\phantom{\text{Decrease}} = 20

\text{Percentage decrease} = \dfrac{20}{400} \times 100\%

= 5\%

Question 5

(a)(i)Answer:

= 93.75\%

[1]

\dfrac{60}{64} \times 100\%

= 93.75\%

(a)(ii)Answer:

= 4\%

[2]

2.5 \text{ kg} = 2.5 \times 1000 \text{ g}

\phantom{2.5 \text{ kg}} = 2500 \text{ g}

\dfrac{100}{2500} \times 100\%

= 4\%

(b)(i)Answer:

= 10\%

[2]

\text{Loss} = 60 - 54

\phantom{\text{Loss}} = 6

\text{Percentage loss} = \dfrac{6}{60} \times 100\%

= 10\%

(b)(ii)Answer:

= 10\%

[2]

\text{Discount} = 400 - 360

\phantom{\text{Discount}} = 40

\text{Percentage discount} = \dfrac{40}{400} \times 100\%

= 10\%

Question 6

(a)Answer: The rent before the increase was $2000.[2]

100\% + 10\% = 110\%

110\% \rightarrow 2200

1\% \rightarrow \dfrac{2200}{110} = 20

100\% \rightarrow 20 \times 100 = 2000

The rent before the increase was $2000.

(b)Answer: The percentage decrease is

4\%

.[3]

100\% + 20\% = 120\% \rightarrow 4320

1\% \rightarrow \dfrac{4320}{120} = 36

100\% \rightarrow 3600

In 2023 the number was

3600

3600 - 3456 = 144

\dfrac{144}{3600} \times 100\% = 4\%

The percentage decrease is

4\%

(c)Answer: It costs $405 more on hire purchase.[3]

\text{Deposit} = \dfrac{25}{100} \times 6000

\phantom{\text{Deposit}} = 1500

18 \times 272.50 = 4905

1500 + 4905 = 6405

6405 - 6000 = 405

It costs $405 more on hire purchase.

Practice questions by skill

Sec 1 Maths Percentage worksheet with answers

In the print window, choose Save as PDF to download it.

Need the formulas first? Read the Percentage notes. Or practise it online with step-by-step help when you get one wrong.

Item

Price

Tom yum soup

$11.80

Teh tarik

$2.80

Lime juice

$3.40

Chendol

$4.40

Section B

(a)The marked price of a rice cooker is $30. During a sale it is sold for $26.25. Find the percentage discount.

Answer (a)%[2]

(b)(i)A family used 20 m³ of water in March. In April they used 25% less. Find the volume of water, in m³, they used in April.

Answer (b)(i)[2]

(b)(ii)A family's monthly electricity bill fell from $400 to $380. Find the percentage decrease.

Answer (b)(ii)%[2]

Hire purchase

Piano

Cash price

$6,000

Deposit

25% of the cash price

Monthly instalments

18 instalments of $272.50

Answers and worked solutions

Question 1

Answer: The interest is $400.[2]

I = \dfrac{PRT}{100}

I = \dfrac{4000 \times 5 \times 2}{100}

= 400

The interest is $400.

Question 2

Answer: The family pays $21.49.[3]

11.80 + 2.80 + 3.40 + 4.40 = 22.40

22.40 \times \dfrac{80}{100} = 17.92

17.92 \times \dfrac{110}{100} = 19.712

19.712 \times \dfrac{109}{100} = 21.48608

\approx 21.49

(to the nearest cent)The family pays $21.49.

Question 3

(a)Answer: They used

14.4

m³ of water in April.[2]

100\% - 20\% = 80\%

\text{New value} = \dfrac{80}{100} \times 18

= 14.4

They used

14.4

m³ of water in April.

(b)Answer: Its price now is $216.[2]

100\% - 10\% = 90\%

\text{New value} = \dfrac{90}{100} \times 240

= 216

Its price now is $216.

Question 4

(a)Answer:

= 12.5\%

[2]

\text{Discount} = 30 - 26.25

\phantom{\text{Discount}} = 3.75

\text{Percentage discount} = \dfrac{3.75}{30} \times 100\%

= 12.5\%

(b)(i)Answer: They used

15

m³ of water in April.[2]

100\% - 25\% = 75\%

\text{New value} = \dfrac{75}{100} \times 20

= 15

They used

15

m³ of water in April.

(b)(ii)Answer:

= 5\%

[2]

\text{Decrease} = 400 - 380

\phantom{\text{Decrease}} = 20

\text{Percentage decrease} = \dfrac{20}{400} \times 100\%

= 5\%

Question 5

(a)(i)Answer:

= 93.75\%

[1]

\dfrac{60}{64} \times 100\%

= 93.75\%

(a)(ii)Answer:

= 4\%

[2]

2.5 \text{ kg} = 2.5 \times 1000 \text{ g}

\phantom{2.5 \text{ kg}} = 2500 \text{ g}

\dfrac{100}{2500} \times 100\%

= 4\%

(b)(i)Answer:

= 10\%

[2]

\text{Loss} = 60 - 54

\phantom{\text{Loss}} = 6

\text{Percentage loss} = \dfrac{6}{60} \times 100\%

= 10\%

(b)(ii)Answer:

= 10\%

[2]

\text{Discount} = 400 - 360

\phantom{\text{Discount}} = 40

\text{Percentage discount} = \dfrac{40}{400} \times 100\%

= 10\%

Question 6

(a)Answer: The rent before the increase was $2000.[2]

100\% + 10\% = 110\%

110\% \rightarrow 2200

1\% \rightarrow \dfrac{2200}{110} = 20

100\% \rightarrow 20 \times 100 = 2000

The rent before the increase was $2000.

(b)Answer: The percentage decrease is

4\%

.[3]

100\% + 20\% = 120\% \rightarrow 4320

1\% \rightarrow \dfrac{4320}{120} = 36

100\% \rightarrow 3600

In 2023 the number was

3600

3600 - 3456 = 144

\dfrac{144}{3600} \times 100\% = 4\%

The percentage decrease is

4\%

(c)Answer: It costs $405 more on hire purchase.[3]

\text{Deposit} = \dfrac{25}{100} \times 6000

\phantom{\text{Deposit}} = 1500

18 \times 272.50 = 4905

1500 + 4905 = 6405

6405 - 6000 = 405

It costs $405 more on hire purchase.