Sec 1 G2 Maths Percentage worksheet with answers

A free Sec 1 G2 Maths worksheet on percentage: 7 questions, 30 marks, short questions first and then structured ones, in the school exam style. The answers and full worked solutions are on the last page.

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Sec 1 G2 Maths worksheet: Percentage

Total: 30 marksSuggested time: 50 minutes

Name: ______________________________Class: ____________ Date: ____________

Answer all questions. Show all your working. Give non-exact answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless the question says otherwise.

Section A

Express

400

g as a percentage of

5

kg.

Answer%[2]

Item	Price
Kopi	$2.40
Sambal kangkong	$12.80
Barley drink	$3.60

The table shows the food a family ordered at a restaurant. A 10% service charge is added to the bill, and then 9% GST is charged on the total. Find the amount the family pays, correct to the nearest cent.

Answer$[2]

Buying the car
List price	$168,000
Dealer's discount	10% of the list price
Registration and other fees	$2,400 (paid in cash)
Down payment	40% of the price after the discount
Car loan	the rest of the price, at 2.4% per annum simple interest for 5 years, paid back in equal monthly instalments

Devi buys a car on the terms in the table. Find the total amount Devi pays for the car, including the fees and the interest.

Answer$[3]

(a)The percentage of households in a town with solar panels rose from 25% to 35%. Find the increase, in percentage points.

Answer (a)[1]

(b)The number of visitors to a museum in 2023 was 8,960. This was 12% more than in 2022. In 2024, the number was 11,200. Find the percentage increase in the number of visitors to a museum from 2022 to 2024.

Answer (b)%[3]

Section B

(a)After a 10% pay rise, Farah earns $3,520 a month. Find her monthly pay before the rise.

Answer (a)$[2]

(b)The mass of a parcel was 8 kg. After repacking, its mass is 9 kg. Find the percentage increase in its mass.

Answer (b)%[2]

(a)Express

125

g as a percentage of

2.5

kg.

Answer (a)%[2]

(b)(i)The number of visitors to a park fell by 40% to 480. Find the number of visitors before the fall.

Answer (b)(i)[2]

(b)(ii)After a 30% price cut, a printer costs $105. Find the amount by which the price was cut.

Answer (b)(ii)$[3]

(a)The price of a cup of kopi fell from $5 to $2. Find the percentage decrease in the price.

Answer (a)%[2]

(b)(i)Siti puts $4,000 in a fixed deposit account that pays 4% per annum simple interest. Find the total amount in the account after 5 years.

Answer (b)(i)$[3]

(b)(ii)Nur deposits $8,000 in a bank that pays simple interest of 2% per annum. Find the interest earned after 42 months.

Answer (b)(ii)$[3]

END OF PAPER

Answers and worked solutions

Question 1

Answer:

= 8\%

[2]

5 \text{ kg} = 5 \times 1000 \text{ g}

\phantom{5 \text{ kg}} = 5000 \text{ g}

\dfrac{400}{5000} \times 100\%

= 8\%

Question 2

Answer: The family pays $22.54.[2]

2.40 + 12.80 + 3.60 = 18.80

18.80 \times \dfrac{110}{100} = 20.68

20.68 \times \dfrac{109}{100} = 22.5412

\approx 22.54

(to the nearest cent)The family pays $22.54.

Question 3

Answer: Devi pays $164,486.40 in total.[3]

\dfrac{90}{100} \times 168000 = 151200

\text{Down payment} = \dfrac{40}{100} \times 151200

\phantom{\text{Down payment}} = 60480

\text{Loan} = 151200 - 60480

\phantom{\text{Loan}} = 90720

I = \dfrac{90720 \times 2.4 \times 5}{100}

\phantom{I} = 10886.40

151200 + 2400 + 10886.40 = 164486.40

Devi pays $164,486.40 in total.

Question 4

(a)Answer: It increased by

10

percentage points.[1]

A change in percentage points is the difference between the two percentages.

35 - 25 = 10

It increased by

10

percentage points.

(b)Answer: The percentage increase is

40\%

.[3]

100\% + 12\% = 112\% \rightarrow 8960

1\% \rightarrow \dfrac{8960}{112} = 80

100\% \rightarrow 8000

In 2022 the number was

8000

11200 - 8000 = 3200

\dfrac{3200}{8000} \times 100\% = 40\%

The percentage increase is

40\%

Question 5

(a)Answer: Her pay before the rise was $3200.[2]

100\% + 10\% = 110\%

110\% \rightarrow 3520

1\% \rightarrow \dfrac{3520}{110} = 32

100\% \rightarrow 32 \times 100 = 3200

Her pay before the rise was $3200.

(b)Answer:

= 12.5\%

[2]

\text{Increase} = 9 - 8

\phantom{\text{Increase}} = 1

\text{Percentage increase} = \dfrac{1}{8} \times 100\%

= 12.5\%

Question 6

(a)Answer:

= 5\%

[2]

2.5 \text{ kg} = 2.5 \times 1000 \text{ g}

\phantom{2.5 \text{ kg}} = 2500 \text{ g}

\dfrac{125}{2500} \times 100\%

= 5\%

(b)(i)Answer: There were

800

visitors before.[2]

100\% - 40\% = 60\%

60\% \rightarrow 480

1\% \rightarrow \dfrac{480}{60} = 8

100\% \rightarrow 8 \times 100 = 800

There were

800

visitors before.

(b)(ii)Answer: The price was cut by $45.[3]

100\% - 30\% = 70\%

70\% \rightarrow 105

1\% \rightarrow \dfrac{105}{70} = 1.5

100\% \rightarrow 1.5 \times 100 = 150

150 - 105 = 45

The price was cut by $45.

Question 7

(a)Answer:

= 60\%

[2]

\text{Decrease} = 5 - 2

\phantom{\text{Decrease}} = 3

\text{Percentage decrease} = \dfrac{3}{5} \times 100\%

= 60\%

(b)(i)Answer: The total amount is $4800.[3]

I = \dfrac{PRT}{100}

I = \dfrac{4000 \times 4 \times 5}{100}

= 800

\text{Amount} = 4000 + 800

\phantom{\text{Amount}} = 4800

The total amount is $4800.

(b)(ii)Answer: The interest is $560.[3]

T = \dfrac{42}{12}

\phantom{T} = 3.5

I = \dfrac{PRT}{100}

I = \dfrac{8000 \times 2 \times 3.5}{100}

= 560

The interest is $560.

Sec 1 G2 Maths Percentage worksheet with answers

In the print window, choose Save as PDF to download it.

Or practise it online with step-by-step help when you get one wrong.

Item

Price

Kopi

$2.40

Sambal kangkong

$12.80

Barley drink

$3.60

Buying the car

List price

$168,000

Dealer's discount

10% of the list price

Registration and other fees

$2,400 (paid in cash)

Down payment

40% of the price after the discount

Car loan

the rest of the price, at 2.4% per annum simple interest for 5 years, paid back in equal monthly instalments

Answers and worked solutions

Question 1

Answer:

= 8\%

[2]

5 \text{ kg} = 5 \times 1000 \text{ g}

\phantom{5 \text{ kg}} = 5000 \text{ g}

\dfrac{400}{5000} \times 100\%

= 8\%

Question 2

Answer: The family pays $22.54.[2]

2.40 + 12.80 + 3.60 = 18.80

18.80 \times \dfrac{110}{100} = 20.68

20.68 \times \dfrac{109}{100} = 22.5412

\approx 22.54

(to the nearest cent)The family pays $22.54.

Question 3

Answer: Devi pays $164,486.40 in total.[3]

\dfrac{90}{100} \times 168000 = 151200

\text{Down payment} = \dfrac{40}{100} \times 151200

\phantom{\text{Down payment}} = 60480

\text{Loan} = 151200 - 60480

\phantom{\text{Loan}} = 90720

I = \dfrac{90720 \times 2.4 \times 5}{100}

\phantom{I} = 10886.40

151200 + 2400 + 10886.40 = 164486.40

Devi pays $164,486.40 in total.

Question 4

(a)Answer: It increased by

10

percentage points.[1]

A change in percentage points is the difference between the two percentages.

35 - 25 = 10

It increased by

10

percentage points.

(b)Answer: The percentage increase is

40\%

.[3]

100\% + 12\% = 112\% \rightarrow 8960

1\% \rightarrow \dfrac{8960}{112} = 80

100\% \rightarrow 8000

In 2022 the number was

8000

11200 - 8000 = 3200

\dfrac{3200}{8000} \times 100\% = 40\%

The percentage increase is

40\%

Question 5

(a)Answer: Her pay before the rise was $3200.[2]

100\% + 10\% = 110\%

110\% \rightarrow 3520

1\% \rightarrow \dfrac{3520}{110} = 32

100\% \rightarrow 32 \times 100 = 3200

Her pay before the rise was $3200.

(b)Answer:

= 12.5\%

[2]

\text{Increase} = 9 - 8

\phantom{\text{Increase}} = 1

\text{Percentage increase} = \dfrac{1}{8} \times 100\%

= 12.5\%

Question 6

(a)Answer:

= 5\%

[2]

2.5 \text{ kg} = 2.5 \times 1000 \text{ g}

\phantom{2.5 \text{ kg}} = 2500 \text{ g}

\dfrac{125}{2500} \times 100\%

= 5\%

(b)(i)Answer: There were

800

visitors before.[2]

100\% - 40\% = 60\%

60\% \rightarrow 480

1\% \rightarrow \dfrac{480}{60} = 8

100\% \rightarrow 8 \times 100 = 800

There were

800

visitors before.

(b)(ii)Answer: The price was cut by $45.[3]

100\% - 30\% = 70\%

70\% \rightarrow 105

1\% \rightarrow \dfrac{105}{70} = 1.5

100\% \rightarrow 1.5 \times 100 = 150

150 - 105 = 45

The price was cut by $45.

Question 7

(a)Answer:

= 60\%

[2]

\text{Decrease} = 5 - 2

\phantom{\text{Decrease}} = 3

\text{Percentage decrease} = \dfrac{3}{5} \times 100\%

= 60\%

(b)(i)Answer: The total amount is $4800.[3]

I = \dfrac{PRT}{100}

I = \dfrac{4000 \times 4 \times 5}{100}

= 800

\text{Amount} = 4000 + 800

\phantom{\text{Amount}} = 4800

The total amount is $4800.

(b)(ii)Answer: The interest is $560.[3]

T = \dfrac{42}{12}

\phantom{T} = 3.5

I = \dfrac{PRT}{100}

I = \dfrac{8000 \times 2 \times 3.5}{100}

= 560

The interest is $560.