Congruent and similar triangles questions with answers
Practice questions on congruent and similar triangles, from the basics up to exam level, each with a full worked solution. Try them on paper first, then open the solution to check your working.
Worked example
PQ is parallel to SR. The lines PS and QR cross at X, and X is the mid-point of PS. Prove that △PQX≡△SRX, and state the congruence test.
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Questions
Question 1Prove two triangles are congruent
The lines EF and GH cross at K, and K is the mid-point of both EF and GH. Prove that △EKG≡△FKH, and state the congruence test.
Show the worked solution
Step 1: Match three pairs of parts, each with its reasonEK=FK (given)∠EKG=∠FKH (vert. opp. ∠s)GK=HK (given)
Step 2: Name the congruence test the three pairs give△EKG≡△FKH (SAS)
Question 2Prove two triangles are congruent
In the diagram, AB=AD and CB=CD. Prove that △ABC≡△ADC, and state the congruence test.
Show the worked solution
Step 1: Match three pairs of parts, each with its reasonAB=AD (given)CB=CD (given)AC=AC (common side)
Step 2: Name the congruence test the three pairs give△ABC≡△ADC (SSS)
Question 3Prove two triangles are similar, then find a length
In triangle KLM, N lies on LM and F lies on KL such that ∠LKN=∠LMF. KL=6 cm, LN=4 cm and NM=2 cm. Prove that △KLN is similar to △MLF. Hence find LF.
Show the worked solution
Step 1: Two pairs of equal angles, each with its reason∠KLN=∠MLF (common ∠)∠LKN=∠LMF (given)
Step 2: Name the similarity test△KLN is similar to △MLF (AA).
Step 3: LM is the whole side: LN + NM(LM=4+2LM=6
Step 4: Matching sides are in the same ratio: write each side of △MLF over its matchLNLF=KLML4LF=66
Step 5: Work out LFLF=4 cm
Question 4Prove two triangles are similar, then find a length
In triangle ABC, D lies on AB and E lies on AC, with DE parallel to BC. AD=3 cm, DB=2 cm and BC=6 cm. Prove that △ADE is similar to △ABC. Hence find DE.
Show the worked solution
Step 1: Two pairs of equal angles, each with its reason∠ADE=∠ABC (corr. ∠s (DE ∥ BC))∠DAE=∠BAC (common ∠)
Step 2: Name the similarity test△ADE is similar to △ABC (AA).
Step 3: AB is the whole side: AD + DB(AB=3+2AB=5
Step 4: Matching sides are in the same ratio: write each side of △ADE over its matchBCDE=ABAD6DE=53